JavaScript異步編程之Jscex制作憤怒的小鳥
Jscex真的能制作憤怒的小鳥?在我沒有接觸Jscex之前,我也不相信!但是只要解決了重力場運(yùn)動和碰撞的兩大物理問題,Jscex版的憤怒小鳥,那就是囊中之物。
51CTO推薦專題:JavaScript異步編程

如果關(guān)注這個系列的話,在javascript異步編程之Jscex模擬重力場與google蘋果logo的比較中,模擬了蘋果在重力場下的自由落體運(yùn)動。
那么我們可以輕松的幫它擴(kuò)展一個水平方向上的速度.
- <script type="text/javascript">
 - function Bird(startPos, speed_X, speed_Y, element) {
 - this.speed_X = speed_X;
 - this.speed_Y = speed_Y;
 - this.startPos = startPos;
 - this.fly = function () {
 - flyAsync(element, startPos, speed_X, speed_Y).start();
 - }
 - }
 - var flyAsync = eval(Jscex.compile("async", function (e, startPos, speed_X, speed_Y) {
 - e.style.left = startPos.x;
 - e.style.top = startPos.y;
 - //vt=v0+at
 - //重力加速度
 - var a_y = 40;
 - var speed_Yspeed_YTemp = speed_Y;
 - var time = 0;
 - while (Math.abs(speed_Y) <= speed_YTemp) {
 - $await(Jscex.Async.sleep(50));
 - timetime = time + 50;
 - speed_Yspeed_Y = speed_Y - a_y;
 - startPos.y -= (speed_Y * 0.05);
 - e.style.top = startPos.y;
 - startPos.x += speed_X * 0.05;
 - e.style.left = startPos.x;
 - }
 - }));
 - function Button1_onclick() {
 - var bird = new Bird({ x: 0, y: 300 }, 400, 700, document.getElementById("birdDiv"));
 - bird.fly();
 - }
 - </script>
 - <input id="Button1" type="button" value="發(fā)¢射?" onclick="return Button1_onclick()" />
 - <div id="birdDiv" style="left: 0px; top: 300px; position: absolute;">
 - <img id="bird" src="bird.jpg" alt="" />
 - </div>
 
可以看得出來,有點(diǎn)生硬,而且位移有點(diǎn)偏差,比如啟始的top:1000,終止的top:1100!主要原因是在結(jié)束while (Math.abs(speed_Y) <= speed_YTemp)的之前那最后一次
循環(huán)帶來的誤差!那么就完善一下while里面的條件,讓它不執(zhí)行最后一次循環(huán)。
- var flyAsync = eval(Jscex.compile("async", function (e, startPos, speed_X, speed_Y) {
 - e.style.left = startPos.x;
 - e.style.top = startPos.y;
 - //vt=v0+at
 - //重力加速度
 - var a_y = 40;
 - var speed_Yspeed_YTemp = speed_Y;
 - var time = 0;
 - var maxY = startPos.y
 - while (speed_Y > 0 ? (Math.abs(speed_Y) <= speed_YTemp) : (e.offsetTop - (speed_Y - a_y) * 0.05 <= maxY)) {
 - $await(Jscex.Async.sleep(50));
 - timetime = time + 50;
 - speed_Yspeed_Y = speed_Y - a_y;
 - startPos.y -= (speed_Y * 0.05);
 - e.style.top = startPos.y;
 - startPos.x += speed_X * 0.05;
 - e.style.left = startPos.x;
 - }
 - }));
 
最后讓小鳥撞擊地面彈起,然后又撞擊地面彈起···一直循環(huán)下去···
- var flyAsync = eval(Jscex.compile("async", function (e, startPos, speed_X, speed_Y) {
 - e.style.left = startPos.x;
 - e.style.top = startPos.y;
 - var maxY = startPos.y;
 - //所用公式?:vt=v0+at
 - //重力加速度
 - var a_y = 40;
 - var speed_Yspeed_YTemp = speed_Y;
 - var time = 0;
 - while (true) {
 - $await(Jscex.Async.sleep(1));
 - while (speed_Y > 0 ? (Math.abs(speed_Y) <= speed_YTemp) : (e.offsetTop - (speed_Y - a_y) * 0.05 <= maxY)) {
 - $await(Jscex.Async.sleep(50));
 - timetime = time + 50;
 - speed_Yspeed_Y = speed_Y - a_y;
 - startPos.y -= (speed_Y * 0.05);
 - e.style.top = startPos.y;
 - startPos.x += speed_X * 0.05;
 - e.style.left = startPos.x;
 - }
 - //與地面撞擊,X軸損失一部分速度,Y軸損失一部分速度并且被彈起
 - speed_Xspeed_X = speed_X / 2;
 - speed_Y = -speed_Y / 3;
 - if (speed_X < 6) break;
 - }
 - }));
 
因?yàn)樽矒舻倪^程當(dāng)中,X軸損失一部分速度,Y軸損失一部分速度并且被彈起,當(dāng)speed_X小于6的時候退出循環(huán)。
黃色小鳥:體型較小,重量較輕,殊效為加快,應(yīng)用進(jìn)步擊弱,應(yīng)用掉隊(duì)擊中等。進(jìn)擊木頭較強(qiáng),進(jìn)擊玻璃與混凝土很弱。

對,沒有錯,它就這這篇文章的主角!
需求解析:沖鋒陷陣鳥,在不點(diǎn)擊加快的景象下,和紅色小鳥樣,當(dāng)點(diǎn)擊了加快按鈕,X軸標(biāo)的目標(biāo)速度變成本來的3倍,Y軸標(biāo)的目標(biāo)變成本來的3倍,
沖鋒狀況下速度不受重力影響。
原理圖:

沖鋒鳥代碼實(shí)現(xiàn):
- <script type="text/javascript">
 - function Bird(startPos, speed_X, speed_Y, element) {
 - this.speed_X = speed_X;
 - this.speed_Y = speed_Y;
 - this.startPos = startPos;
 - this.fly = function () {
 - flyAsync(element, startPos, speed_X, speed_Y).start();
 - }
 - }
 - var flyAsync = eval(Jscex.compile("async", function (e, startPos, speed_X, speed_Y) {
 - document.getElementById("hdTag").value = 1;
 - e.style.left = startPos.x;
 - e.style.top = startPos.y;
 - var maxY = startPos.y;
 - //重?力|加ó速ù度è
 - var a_y = 40;
 - var speed_Yspeed_YTemp = speed_Y;
 - var speed_Xspeed_XTemp = speed_X;
 - var time = 0;
 - var addTag = 1;
 - while (true) {
 - $await(Jscex.Async.sleep(1));
 - while ((e.offsetTop - (speed_Y - a_y) * 0.05 <= maxY)) {
 - if (document.getElementById("hdTag").value == 1) {
 - $await(Jscex.Async.sleep(50));
 - timetime = time + 50;
 - speed_Yspeed_Y = speed_Y - a_y;
 - startPos.y -= (speed_Y * 0.05);
 - startPos.x += speed_X * 0.05;
 - e.style.top = startPos.y + "px";
 - e.style.left = startPos.x + "px";
 - }
 - else {
 - //沖?鋒?狀′態(tài)?
 - $await(Jscex.Async.sleep(50));
 - timetime = time + 50;
 - if (addTag == 1) {
 - addTag = 0;
 - //速ù度è翻-倍?
 - speed_Y = 3 * speed_Y;
 - speed_X = 3 * speed_X;
 - }
 - startPos.y -= (speed_Y * 0.05);
 - startPos.x += speed_X * 0.05;
 - e.style.top = startPos.y + "px";
 - e.style.left = startPos.x + "px";
 - }
 - }
 - if (addTag == 0) {
 - addTag = 1; break;
 - }
 - //與?地?面?撞2擊÷,?X軸á損e失§一?部?分?速ù度è,?Y軸á損e失§一?部?分?速ù度è并¢且ò被?彈ˉ起e
 - document.getElementById("hdTag").value = 1;
 - speed_Xspeed_X = speed_X / 2;
 - speed_Y = -speed_Y / 3;
 - if (speed_X < 6) break;
 - }
 - }));
 - function Button1_onclick() {
 - var bird = new Bird({ x: 0, y: 500 }, 400, 700, document.getElementById("birdDiv"));
 - bird.fly();
 - }
 - function Button2_onclick() {
 - document.getElementById("hdTag").value = 0;
 - }
 - </script>
 - <div >
 - <input id="hdTag" value="1" type="hidden" />
 - <input id="Button1" type="button" value="發(fā)¢射?" onclick="return Button1_onclick()" />
 - <input id="Button2" type="button" value="加ó速ù" onclick="return Button2_onclick()" />
 - <div id="birdDiv" style="left: 0px; top: 500px; position: absolute; width: 20px;
 - height: 30px;z-index:10;">
 - <img src="yellowbird.png" alt=""/>
 - </div>
 - </div>
 
最新的Jscex 庫,請上https://github.com/JeffreyZhao/jscex或者h(yuǎn)ttp://www.sndacode.com/projects/jscex/wiki下載吧····
原文:http://www.cnblogs.com/iamzhanglei/archive/2011/08/24/2151473.html
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